Question

помогите 9 класс матеша​

Answer 1

$52-x^2+x=10\\52-x^2+x-10=0\\x^2-x-42=0\\x^2+6x-7x-42=0\\x(x+6)-7(x+6) = 0\\(x-7)(x+6) = 0\\x+6=0\\x-7=0\\x_1=-6\\x_2=7$

$2-\dfrac{3x-7}{4} =-\dfrac{x+17}{5} ~~~~~~~~ | * 20\\\\40-5(3x-7)=-4(x+17)\\40-15x+35=-4x-68\\-15x+4x=-68-75\\-11x=-143\\x=13$

Answer 2

1) 52-х²+х=10

52-х²+х-10=0

42-х²+х=0

-42+х²+х=0

х²-х-42=0

х²+6х-7х-42=0

х×(х+6)-7×(х+6)=0

(х+6)×(х-7)=0

х+6=0

х-7=0

х=-6

х=7

х1=-6,х2=7

2) 2-3х-7/4=х+17/5

40-5×(3х-7)=4×(х+17)

40-15х+35=4х+68

75-15х=4х+68

15х-4х=68-75

-19х=-7

х=7/19