Question

помогите пж с 12 13 кроме а​

Answer 1

Ответ:

b)

${4}^{ \frac{5}{12} } \times \sqrt[6]{2} = ({2}^{2})^{ \frac{5}{12} } \times {2}^{ \frac{1}{6} } = {2}^{2 \times \frac{5}{12} + \frac{1}{6} } = 2^{ \frac{5}{6} + \frac{1}{6} } = 2^{ \frac{6}{6} } = 2$

c)

${25}^{0.7} \times 5^{0.4} = (5^{2})^{0.7} \times 5^{0.4} = {5}^{2 \times 0.7 + 0.4} = {5}^{1.8}$

d)

${3}^{0.2} \times {3}^{ - 0.25} \times {3}^{ \frac{4}{5} } \times {3}^ { - \frac{3}{4} } = 3^{0.2 - 0.25 + \frac{4}{5} - \frac{3}{4} } = {3}^{ \frac{1}{5} - \frac{1}{4} + \frac{4}{5} - \frac{3}{4} } = {3}^{ \frac{5}{5} - \frac{4}{4} } = 3^{1 - 1} = {3}^{0} = 1$

b)

$( \frac{1}{8} \times {27}^{ - 1} )^{ \frac{1}{3} } = ( \frac{1}{8} \times \frac{1}{27} )^{ \frac{1}{3} } = \sqrt[3]{ \frac{1}{8} \times \frac{1}{27} } = \sqrt[3]{ \frac{1}{8} } \times \sqrt[3]{ \frac{1}{27} } = \frac{1}{2} \times \frac{1}{3} = \frac{1}{6}$

c)

$(0.01 \times \frac{1}{49} )^{ - \frac{1}{2} } = ( \frac{1}{100} \times \frac{1}{49} )^{ - \frac{1}{2} } = (100 \times 49)^{ \frac{1}{2} } = \sqrt{100 \times 49} = \sqrt{100} \times \sqrt{49} = 10 \times 7 = 70$

d)

$( \frac{49}{144} )^{ \frac{1}{2} } = \sqrt{ \frac{49}{144} } = \frac{ \sqrt{49} }{ \sqrt{144} } = \frac{7}{12}$