Question

Помогите решить пожалуйста 6 класс математика​

Answer 1

Ответ:

1)$\frac{1}{4}+\frac{3}{5}=\frac{5}{20}+\frac{12}{20}= \frac{17}{20}$

2)$\frac{9}{11}-\frac{9}{5}=\frac{45}{55}-\frac{99}{55}=-\frac{54}{55}$

3)$\frac{3}{16}-\frac{9}{32}=\frac{6}{32}-\frac{9}{32} =-\frac{3}{32}$

4)$\frac{3}{28}+\frac{5}{14}= \frac{3}{28}+\frac{10}{28}=\frac{13}{28}$

5)$\frac{14}{15} -\frac{7}{10}= \frac{28}{30}-\frac{21}{30}=\frac{7}{30}$

6)$\frac{3}{8}+\frac{1}{6}=\frac{9}{24}+\frac{4}{24} =\frac{13}{24}$

7)$\frac{9}{25}-\frac{7}{20} = \frac{36}{100}-\frac{35}{100}=\frac{1}{100}$

8)$\frac{37}{42} -\frac{17}{24}=\frac{37*4}{168}-\frac{17*7}{168} =\frac{148}{168}-\frac{119}{168} =\frac{29}{168}$

9)$\frac{11}{24}-\frac{3}{16}=\frac{22}{48}-\frac{9}{48} = \frac{13}{48}$

10)$\frac{9}{16}+\frac{7}{24} -\frac{3}{8} = \frac{27}{48}+\frac{14}{48}-\frac{18}{48} =\frac{23}{48}$

11)$\frac{1}{3}-\frac{1}{6}+\frac{1}{4}=\frac{4}{12}-\frac{2}{12}+\frac{3}{12} =\frac{5}{12}$

12)$\frac{2}{5}+\frac{4}{15}-\frac{5}{9}=\frac{18}{45}+\frac{12}{45}-\frac{25}{45}=\frac{5}{45}=\frac{1}{9}$