Question

помогите пожалуйста умоляю​

Answer 1

Ответ:

Пошаговое объяснение:

$(2x-\sqrt{2})^{2} -18=0\\\\(2x-\sqrt{2})^{2} =18\\(2x-\sqrt{2}-\sqrt{18})(2x-\sqrt{2}+\sqrt{18}) =0\\(2x-\sqrt{2}-3\sqrt{2})(2x-\sqrt{2}+3\sqrt{2})=0\\(2x-4\sqrt{2})(2x-2\sqrt{2})=0\\2x_{1}-4\sqrt{2}=0;\\2x_{1}=4\sqrt{2}\\x_{1} =2\sqrt{2} \\2x_{2}-2\sqrt{2}=0;\\2x_{2}=2\sqrt{2}\\x_{2} =\sqrt{2}$