Question

ПОМОГИТЕ ЛЮДИ! СРОЧНО!

Answer 1

$1)\sqrt[3]{21\frac{1}{3}}*\sqrt[3]{3}*\sqrt[4]{39\frac{1}{16}}=\sqrt[3]{\frac{64}{3}*3}*\sqrt[4]{\frac{625}{16}}=\sqrt[3]{64}*\sqrt[4]{(\frac{5}{2})^{4}} =\sqrt[3]{4^{3}} *\frac{5}{2} =\\\\=4*\frac{5}{2}=10$

$2)(\frac{1}{\sqrt[6]{a} -\sqrt[6]{b}}-\frac{1}{\sqrt[6]{a}+\sqrt[6]{b}})*(\sqrt[3]{a}-\sqrt[3]{b} )=\frac{\sqrt[6]{a}+\sqrt[6]{b}-\sqrt[6]{a}+\sqrt[6]{b}}{(\sqrt[6]{a}-\sqrt[6]{b})(\sqrt[6]{a}+\sqrt[6]{b})}*(\sqrt[3]{a}-\sqrt[3]{b})=\\\\=\frac{2\sqrt[6]{b}}{(\sqrt[6]{a})^{2}-(\sqrt[6]{b})^{2}}*(\sqrt[3]{a}-\sqrt[3]{b})=\frac{2\sqrt[6]{b}}{\sqrt[3]{a}-\sqrt[3]{b}}*(\sqrt[3]{a}-\sqrt[3]{b})=2\sqrt[6]{b}$

$3)\frac{\sqrt[4]{48}}{\sqrt[4]{3}}*\sqrt[3]{-3\frac{3}{8}}:\frac{\sqrt[3]{-216}}{\sqrt[10]{1024}} =\sqrt[4]{\frac{48}{3}}*\sqrt[3]{-\frac{27}{8}}:\frac{\sqrt[3]{(-6)^{3}}}{\sqrt[10]{2^{10}}}=\sqrt[4]{16}*\sqrt[3]{(-\frac{3}{2})^{3}}:\frac{-6}{2}=\\\\=2*(-\frac{3}{2} ):(-3)= 2*3:3=2$