Question

РЕШИТЕ ПЖ ДАЮ 20 БАЛЛОВ

Answer 1

Номер 4

$\frac{ {x}^{14} {y}^{6} }{ {x}^{7} {y}^{3} } = {x}^{7} {y}^{3} \\ x = 1 \: \: = > \: \: {x}^{7} {y}^{3 } = {1}^{7} {y}^{3} = {y}^{3}$

Номер 5

$0.16 \times ( - 10 {)}^{2} - {2}^{2} = \\ 0.16 \times 100 - 4 = 16 - 4 = 12$

Answer 2

Ответ:

$\frac{x^{14}y^6}{x^7y^3} = x^7y^3\\\\1^7*y^3 = y^3$

$0.16*(-10)^2-2^2 = 0.16*100-4 = 16-4 = 12$