Question

помогите пожалуйста умоляюю​

Answer 1

$(3x - 5) {}^{2} = 16 \\ (3x - 5) {}^{2} - 16 = 0 \\ (3x - 5 - 4)(3x - 5 + 4) = 0 \\ \\ 3x - 5 - 4 = 0 \\ 3x - 9 = 0 \\ 3x = 9 \\ x = 9 \div 3 \\ x _{1} = 3 \\ \\ 3x - 5 + 4 = 0 \\ 3x - 1 = 0 \\ 3x = 1 \\ x _{2}= \frac{1}{3} \\ \\ otvet \: \: \frac{1}{3} \: \: \: \: 3$