Question

Помогите, пожалуйста!!!

Answer 1

Ответ:

$1.\;\;\frac{3}{2x^2+2x}+\frac{2x-1}{x^2-1}-\frac{2}{x}=\frac{3x-3+4x^2-2x}{2x(x+1)(x-1)}-\frac{2}{x}=\frac{4x^2+x-3-4x^2+4}{2x(x+1)(x-1)}=\frac{(x+1)}{2x(x+1)(x-1)}=\\\\=\frac{1}{2x(x-1)} \\\\\\2.\;\;\frac{x^2+2x+1}{18x^3}*\frac{9x^4}{x^2-1} = \frac{(x+1)^2}{2}*\frac{x}{(x+1)(x-1)} = \frac{x(x+1)}{2(x-1)}$

$3.\;\;\frac{a^3-2a^2}{3a+3}:\frac{a^2-4}{3a^2+6a+3}=\frac{a^2(a-2)}{3(a+1)}*\frac{3(a+1)^2}{(a+2)(a-2)} = \frac{a^2(a+1)}{a+2}$