Question

помогите пожалуйста ​

Answer 1

Решение:

№1)

а)

x^2 + 25 = 10x

x^2 - 10x + 25 = 0

(x - 5)^2 = 0

x = 5

б)

6 + 3x = |x + 2|

$\left \{ {{x + 2 >= 0} \atop {6 + 3x = x + 2}} \right.$   $\left \{ {{x >= -2} \atop {2x = -4}} \right.$  $\left \{ {{x >= -2} \atop {x = -2}} \right.$

$\left \{ {{x + 2 < 0} \atop {6 + 3x = -x - 2}} \right.$ $\left \{ {{x < -2} \atop {4x = -8}} \right.$  $\left \{ {{x < -2} \atop {x = -2}} \right.$

x = -2

№2)

а)

(10 - 4x)(8x - 6) = 0

$\left \{ {{10 - 4x = 0} \atop {8x - 6 = 0}} \right.$

$\left \{ {{4x = 10} \atop {8x = 6}} \right.$

$\left \{ {{x = 2,5} \atop {x = 0,75}} \right.$

Ответ: 2,5; 0,75.

б)

$\frac{3x - 4}{7} = \frac{7 - 2x}{8}$

(3x - 4)*8 = (7 - 2x)*7

24x - 32 = 49 - 14x

38x = 81

x = $\frac{81}{38}$

Ответ: $\frac{81}{38}$