Question

Помогите добрые люди) +25баллов

Answer 1

Ответ:

Объяснение:

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Answer 2

$7)\ \ a>0\ ,\ \ b>0\ ,\ \ a\ne b\\\\\\\Big(\dfrac{a}{\sqrt{ab}-b}-\dfrac{\sqrt{b}}{\sqrt{b}-\sqrt{a}}\Big)\cdot \dfrac{(\sqrt{a}-\sqrt{b})\cdot b}{a+b}=\Big(\dfrac{a}{\sqrt{b}\cdot (\sqrt{a}-\sqrt{b})}-\dfrac{\sqrt{b}}{\sqrt{b}-\sqrt{a}}\Big)\cdot \dfrac{(\sqrt{a}-\sqrt{b})\cdot b}{a+b}=\\\\\\=\dfrac{a+b}{\sqrt{b}\cdot (\sqrt{a}-\sqrt{b})}\cdot \dfrac{(\sqrt{a}-\sqrt{b})\cdot b}{a+b}=\dfrac{b}{\sqrt{b}}=\sqrt{b}$