Question

З розв'язком будь ласка)) СРОЧНО​

Answer 1

Ответ:

B

Объяснение:

$\displaystyle\\\frac{2x}{x^2-y^2}-\frac{2x-y}{x^2-xy}=\frac{2x}{(x-y)(x+y)}-\frac{2x-y}{x(x-y)}=\\\\\\=\frac{2x^2-(x+y)(2x-y)}{x(x-y)(x+y)}=\frac{2x^2-2x^2-2xy+xy+y^2}{x(x-y)(x+y)}=\\\\\\=\frac{-xy+y^2}{x(x-y)(x+y)}= \frac{-y(x-y)}{x(x-y)(x+y)}=-\frac{y}{x(x+y)}$