Question

Помогите пожалуйста, срочно!!!

Answer 1

Ответ:

1а)

$= \frac{7a + 2b + 2a - 5b}{3ab} = \frac{9a - 3b}{3ab} = \frac{3(3a - b)}{3ab} = \frac{3a - b}{ab}$

1б)

$= \frac{9 }{m - n} + \frac{2}{m - n} = \frac{9 + 2}{m - n} = \frac{11}{m - n}$

1в)

$= \frac{ - 8c + 7c - d}{ {c}^{2} - {d}^{2} } = \frac{ - c - d}{ {c}^{2} - {d}^{2} } = - \frac{(c + d)}{(c + d)(c - d)} = - \frac{1}{c - d} = \frac{1}{d - c}$

1г)

$= \frac{8y - 16 - {y}^{2} }{ {y}^{2} - 16} = \frac{ - ( {y}^{2} - 8y + 16)}{ {y}^{2} - 16 } = \frac{ - {(y - 4)}^{2} }{(y - 4)(y + 4)} = \frac{ - (y - 4)}{y + 4} = \frac{4 - y}{y + 4}$

2а)

$= \frac{6x - 21 + 4 - 6x}{54x} = \frac{ - 17}{54x} = - \frac{1}{3x}$

2б)

$= \frac{ab - a - ab - 2b}{ {a}^{2} {b}^{2} } = - \frac{a + 2b}{ {a}^{2} {b}^{2} }$

2в)

$= \frac{7 - p}{7p - {p}^{2} } = \frac{7 - p}{p(7 - p)} = \frac{1}{p}$

2г)

$= \frac{5 {m}^{2} - 10m - 5 {m}^{2} }{m - 2} = \frac{ - 10m}{m - 2} = \frac{10m}{2 - m}$

3)

$= \frac{2x + 1}{3(x - 1)} + \frac{2 + 3x}{5( 1 - x)} = \frac{10x + 5 - 6 - 9x}{15(x - 1)} = \frac{x - 1}{15(x - 1)} = \frac{1}{15}$