Question

помогите пж даю 30 баллов

Answer 1

$\displaystyle arccos(-\frac{\sqrt{2} }{2} )+arcsin(-0.5)=\pi -arccos(\frac{\sqrt{2} }{2} )-arcsin(0.5)=\\\\=\pi-\frac{\pi}{4} -arcsin(\frac{1}{2} )=\pi -\frac{\pi }{4} -\frac{\pi}{6} =\boxed{\frac{7\pi}{12} }$