Question

Помогите срочно надо ​

Answer 1

1

а) f(x)=x+$\frac{1}{x}$    x≠0

f(-1)=-1+$\frac{1}{(-1)}$=-1-1=-2

f(0.5)=0.5+$\frac{1}{0.5}$=0.5+2=2.5

f(10)=10+$\frac{1}{10}$=10.1

б) y(x)=$\sqrt{5x-x^{2} }$       5x-x²≥0

y(0)=$\sqrt{5*0-0^{2} } =0$

y(1)=$\sqrt{5*1-1^{2} } =\sqrt{4} =2$

y(2)=$\sqrt{5*2-2^{2} } =\sqrt{10-4} =\sqrt{6}$

в) g(x)=2-sin(2x)

g(-$\frac{\pi }{4}$)=2+sin($\frac{\pi }{2}$)=2+1=3

g(0)=2-sin(0)=2

g($\frac{5\pi }{12}$)=2-sin($\frac{5\pi }{6}$)=2-0.5=1.5

2) а) f(x)=$\frac{x-1}{x+8}$     x+8≠0 ⇒x≠-8

б) g(x)=$\sqrt{x^{2} -9}$    

x²-9≥0

(x-3)(x+3)≥0   x∈(-∞; -3]∪[3;+∞)