Question

Докажите равенство.

Теңдікті дәлелдеңіз.
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Answer 1

$\frac{10}{\sqrt{6} -1} =\frac{10(\sqrt{6} +1)}{(\sqrt{6} -1)(\sqrt{6} +1)} =\frac{10(\sqrt{6} +1)}{6-1} =\frac{10(\sqrt{6} +1)}{5}=2(\sqrt{6} +1)$

$2(\sqrt{6} +1)=2(\sqrt{6} +1)$

Answer 2

Объяснение:

$\frac{10}{\sqrt{6}-1 }=\frac{10*(\sqrt{6}+1) }{(\sqrt{6}-1)*(\sqrt{6}+1) }=\frac{10*(\sqrt{6}+1) }{(\sqrt{6})^2-1^2 }=\frac{10*(\sqrt{6}+1) }{6-1} =\frac{10*(\sqrt{6}+1) }{5}=2*(\sqrt{6}+1).$