Question

Даю 60 балов пожалуста поможить там легко

Answer 1

а)

$\frac{b-a}{ab} +\frac{b-a}{b^{2}} =\frac{b(b-a)}{ab^{2}} +\frac{a(b-a)}{ab^{2}} =\frac{b^{2}-ab+ab-a^{2}}{ab^{2}} =\frac{b^{2}-a^{2}}{ab^{2}}$

б)

$x^{2}+\frac{2x^{2}}{x-2} =\frac{x^{2}(x-2)}{x-2} +\frac{2x^{2}}{x-2}=\frac{x^{3}-2x^{2}+2x^{2}}{x-2} =\frac{x^{3}}{x-2}$

в)

$\frac{15b-2}{10b^{2}} +\frac{5+b}{5b^{3}} =\frac{b(15b-2)}{10b^{3}} +\frac{2(5+b)}{10b^{3}} =\frac{15b^{2}-2b+10+2b}{10b^{3}} =\frac{15b^{2}+10}{10b^{3}} =\frac{5(3b^{2}+2)}{10b^{3}} =\frac{3b^{2}+2}{2b^{3}}$

г)

$x-3-\frac{x^{2}-x}{x+2} =\frac{(x-3)(x+2)}{x+2} -\frac{x^{2}-x}{x+2}=\frac{x^{2}-x-6-x^{2}+x}{x+2} =-\frac{6}{x+2}$

д)

$\frac{11+3a^{2}}{33a^{2}b} -\frac{2b^{2}+11}{22ab^{2}} =\frac{2b(11+3a^{2})}{66a^{2}b^{2}} -\frac{3a(2b^{2}+11)}{66a^{2}b^{2}} =\frac{22b+6a^{2}b-6ab^{2}-33a}{66a^{2}b^{2}} =$

е)

$\frac{2y^{3}-3}{y^{2}} -2y+3=\frac{2y^{3}-3}{y^{2}}-\frac{2y^{3}}{y^{2}} +\frac{3y^{2}}{y^{2}} =\frac{2y^{3}-3-2y^{3}+3y^{2}}{y^{2}}= \frac{3y^{2}-3}{y^{2}}$