Question

ПОМОГИТЕ РЕШИТЬ!!!!!!!!

Answer 1

Ответ:   $\alpha =\pi *n-arctg(\frac{1}{2}).$

$\frac{2sin\alpha +cos\alpha +1}{4sin\alpha +2cos\alpha +3}=\frac{1}{3};\\\\3*(2sin\alpha +cos\alpha +1)=1*(4sin\alpha +2cos\alpha +3),\\6sin\alpha +3cos\alpha +3=4sin\alpha +2cos\alpha +3,\\6sin\alpha-4sin\alpha +3cos\alpha-2cos\alpha=3-3,\\2sin\alpha +cos\alpha=0,\\2sin\alpha =-cos\alpha, |:cos\alpha ,\\2tg=-1,\\tg=-\frac{1}{2};\\\\\alpha =arctg(-\frac{1}{2})+\pi *n,\\\alpha =\pi *n-arctg(\frac{1}{2}).$