Question

f(x)=(2x+3)(4x-2) f'(x),f(2)

Answer 1

$\displaystyle f(x)=(2x+3)(4x-2)$

$\displaystyle f'(x)=(2x+3)'*(4x-2)+ (2x+3)*(4x-2)' = 2*(4x-2)+(2x+3)*4 = 8x-4+8x+12=16x+8=8*(2x+1)$

$\displaystyle f'(2)=8*(2*2+1) = 8*5 = 40$