Question

Найдите у′(0) + у′(1), если у(х) = 2х3 – 3х2 +5

Answer 1

$y(x) = 2{x}^{3} - 3 {x}^{2} + 5$

$y'(x) = 6 {x}^{2} - 6x = 6x \times (x - 1)$

$y'(0) = 6 \times 0 \times (0 - 1) = 0$

$y'( 1) = 6 \times (1) \times ( 1 - 1) = 6 \times 0= 0$

$y'(0)+y'(1)=0+0=0$