Question

как можно скорее, друзья ​

Answer 1

Объяснение:

$\left \{ {{|x|\geq 4 } \atop {x^2-x-12\leq 0}} \right. \ \ \ \ \left\{\begin{array}{ccc}x\geq 4\\-x\geq 4\ |*(-1)\\x^2-4x+3x-12\leq 0\end{array}\right\ \ \ \ \left\{\begin{array}{ccc}x\geq 4\\x\leq - 4\\x*(x-4)+3*(x-4)\leq 0\end{array}\right\\\left \{ {{-4\leq x\geq 4} \atop {(x-4)*(x+3)\leq 0}} \right. \ \ \ \ \left \{ {{x\in(-\infty;-4]U[4;+\infty)} \atop {x\in[-3;4]}} \right. \Rightarrow.$

Ответ: x=4.