Question

p^2+2pq+q^2/2p * 2p/p^2-q^2​

Answer 1

$\frac{ {p}^{2} + 2pq + {q}^{2} }{2p} \times \frac{2p}{ {p}^{2} - {q}^{2} } = \frac{ {(p + q)}^{2} }{1} \times \frac{1}{(p + q)(p - q)} = \frac{p + q}{p - q}$