Question

помогите плиз последние балы отдаю ​

Answer 1

$\frac{2\sqrt{3}-3\sqrt{2}-\sqrt{6}}{2-\sqrt{6}-\sqrt{2}}=\frac{(\sqrt{2})^{2}*\sqrt{3}-(\sqrt{3})^{2} \sqrt{2}-\sqrt{6}}{(\sqrt{2})^{2}-\sqrt{6}-\sqrt{2}}=\frac{\sqrt{6}(\sqrt{2}-\sqrt{3}- 1) }{\sqrt{2}(\sqrt{2}-\sqrt{3}-1)}=\frac{\sqrt{6}}{2}=\frac{\sqrt{2}*\sqrt{3}}{\sqrt{2}}=\sqrt{3}\\\\Otvet:\boxed{\sqrt{3}}$