Question

log4(9)+2log4(8)-2log4(3)​

Answer 1

$log_{4}(9) + 2 log_{4}(8) - 2 log_{4}(3) = log_{4}(9) + log_{4}( {8}^{2} ) - log_{4}( {3}^{2} ) = log_{4}( \frac{9 \times {8}^{2} }{ {3}^{2} } ) = log_{4}( {8}^{2} ) = log_{ {2}^{2} }(( {2}^{3} ) {}^{2} ) = \frac{1}{2} log_{2}( {2}^{6} ) = \frac{6}{2} log_{2}(2) = 3$

Ответ: 3