Question

(4x²+2x+6)-(3x²-2x+7)

Answer 1

Ответ:

$(4 {x}^{2} + 2x + 6) - (3 {x}^{2} - 2x + 7) = 4 {x}^{2} + 2x + 6 - 3 {x}^{2} + 2x - 7 = {x}^{2} + 4x - 1$