Question

Даю 20 баллов,помогите пожалуйста

Answer 1

Ответ:

${x}^{2} = 4 \\ x = - . + 2$

${x}^{2} = 17 \\ x = - . + \sqrt{17}$

$(x - 8) ^{2} = 0 \\ x - 8 = 0 \\ x = 8$

${x}^{2} = - 36 \\ ne \: mojet \: resheniyem$

${(x + 3)}^{2} = 100 \\ x + 3 = 10 \\ x = 10 - 3 \\ x = 7$

${(x - 4)}^{2} = 6 \\ 1)x - 4 = \sqrt{6} \\ x = \sqrt{6} + 4 \\ 2)x - 4 = - \sqrt{6} \\ x = 4 - \sqrt{6}$

$\sqrt{6x - 3} = 0 \\ 6x - 3 = 0 \\ 6x = 3 \\ x = 3 \div 6 \\ x = \frac{1}{2}$

$\sqrt{6x - 3} = 2 \\ {( \sqrt{6x - 3} )}^{2} = {2}^{2} \\ 6x - 3 = 4 \\ 6x = 7 \\ x = \frac{7}{6}$

$\frac{21}{ \sqrt{x} } = 3 \\ 3 \sqrt{x} = 21 \\ \sqrt{x} = 21 \div 3 \\ \sqrt{x} = 7 \\ x = 49$

$\frac{10}{ \sqrt{x - 4} } = 5 \\ 5 \sqrt{x - 4} = 10 \\ \sqrt{x - 4} = 10 \div 5 \\ \sqrt{x - 4} = 2 \\ x - 4 = 4 \\ x = 8$