Question

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$\frac{x^{2} -4}{9x-18} =0$

Answer 1

$\frac{x^{2} -4}{9x-18}=0\\\\\left \{ {{x^{2}-4=0} \atop {9x-18\neq 0}} \right.\\\\\left \{ {{(x+2)(x-2)=0} \atop {9x\neq 18}} \right.\\\\\left \{ {{\left[\begin{array}{ccc}x+2=0\\x-2=0\end{array}\right} \atop {x\neq2}} \right.\\\\\\\left \{ {{\left[\begin{array}{ccc}x_{1}=-2 \\x_{2}=2-neyd \end{array}\right} \atop {x\neq 2}} \right. \\\\Otvet:\boxed{-2}$