Question

y^3-5y=0

(5-x)(x+5)+x(x-10)=25

(3-2x)^2=(2x-3)(1-6x)
Решите срочно

Answer 1

y^3-5y=0
y(y^2-5)=0
y=0 y=√5  y=-√5
25-x^2+x^2-10x=25
-10x=0
x=0
9+4x^2-12x=-12x^2-3+20x
16x^2-32x+12=0
4x^2-8x+3=0
x=(4+-2)/4
x1=1/2  x2=3/2