Question

Помогите пожалуйста​

Answer 1

Ответ:

$1.\;\;1)\;\;-a(b-5) = -ab+5a\\\\2)\;\;3(a-2b+3c) = 3a-6b+9c\\\\3)\;\;0.5(2a-4b)-(a-5) = a-2b-a+5\\\\4)\;\;-2(1.5c-6)+(7-3c) = -3c+12+7-3c\\\\5)\;\;2(4-a)+8(b-1) = 8-2a+8b-8\\\\\\2.\;\;11\frac{1}{63}*9-12\frac{1}{35}*5= 99\frac{1}{7} -60\frac{1}{7} = 39\\\\\\3.\;\;1)\;-2(x-4)=-2x+8\\\\2)\;\;a(-3b+2c-7) = -3ab+2ac-7a\\\\3)\;\;-1.5(2x-4y) = -3x+6y\\\\4)\;\;3(-4x+6)-(1-12x) = -12x+18-1+12x\\\\5)\;\;2(7-y)+7(x-2) = 14-2y+7x-14$

$4.\;\;11\frac{1}{63}*7-13\frac{1}{45}*5=77\frac{1}{9}-65\frac{1}{9}=12$