Question

Решите уравнение:

(х - 2)(х - 3) - (х + 1)(х - 4) = 0

Ответ: ?

Answer 1

$(x - 2)(x - 3) - (x + 1)(x - 4) = 0$

$( {x}^{2} - 3x - 2x + 6) - ( {x}^{2} - 4x + x - 4) = 0$

${x}^{2} - {x}^{2} - 3x - 2x + 4x - x + 6 + 4 = 0$

$- 2х + 10 = 0$

$10 = 2x$

$x = 5$