Question

Помоги те очень срочно!!!

Answer 1

$\left\{\begin{array}{l}\sqrt[3]{x}\cdot \sqrt{y}=-18\\\sqrt[3]{x}+\sqrt{y}=3\end{array}\right\ \ \ ODZ:\ y\geq 0\ \ ,\ \ t=\sqrt[3]{x}\ ,\ p=\sqrt{y}\geq 0\ ,\\\\\\\left\{\begin{array}{l}t\cdot p=-18\\t+p=3\end{array}\right\ \ \left\{\begin{array}{l}(3-p)\cdot p=-18\\t=3-p\end{array}\right\ \ \left\{\begin{array}{l}p^2-3p-18=0\\t=3-p\end{array}\right$

$\left\{\begin{array}{l}p_1=-3\ ,\ p_2=6\\t_1=6\ ,\ t_2=-3\end{array}\right\ \ \left\{\begin{array}{l}\sqrt{y}=6\\\sqrt[3]{x}=-3\end{array}\right\ \ \left\{\begin{array}{l}y=36\\x=-27\end{array}\right\\\\\\Otvet:\ \ (-27\, ;\, 36\, )\ .$