Question

Дана f(x) = 2 cos x - 3 sin x. Найдите f'(π/2)

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Answer 1

Ответ:

$f'(x) = - 2 \sin(x) - 3 \cos(x) \\ f'( \frac{\pi}{2} ) = - 2 \sin( \frac{\pi}{2} ) - 3 \cos( \frac{\pi}{2} ) = - 2 - 0 = - 2$