Question

срочно помощь!!!!!!!!!!!!!!!!!!!!

Answer 1

Ответ:

решение на фотографии

Answer 2

Ответ:

$x_1 = \frac{18}{5}, x_2 = \frac{81}{44}$

Пошаговое объяснение:

$\sqrt{\frac{60x-1}{x+5} } + 20\sqrt\frac{x+5} {60x-1} = 9\\t = \sqrt{\frac{60x-1}{x+5} } , t > 0\\t+20t^{-1} = 9\\\\\frac{t^2+20-9t}{t}=0\\t^2-9t+20 = 0\\D=81-4*20*1 = 1\\t_1 = \frac{9 + 1}{2} = 5, t_2 = \frac{9-1}{2} = 4 \\\\\sqrt{\frac{60x-1}{x+5} } = 5\\------------\\OD3:\\\left \{ {{x+5\neq 0} \atop {\frac{60x-1}{x+5} > 0} \right. \\\\xc(-\infty, -5)U(\frac{1}{60}, +\infty )\\------------\\\frac{60x-1}{x+5} = 25\\60x-1 = 25x+125\\35x = 126\\x_1 = \frac{18}{5}$

$\sqrt{\frac{60x-1}{x+5} } = 4\\\\\frac{60x-1}{x+5} = 16\\60x-1 = 16x+80\\44x = 81\\x_2 = \frac{81}{44}$