Question

Помогите ПЖЛ братишки

Answer 1

$(2^{2\sqrt{3}}-4^{\sqrt{3}-1})*2^{-2\sqrt{3}}=(2^{2\sqrt{3}}-(2^{2} )^{\sqrt{3}-1})*2^{-2\sqrt{3}}=(2^{2\sqrt{3}}-2^{2\sqrt{3}-2})*2^{-2\sqrt{3}}=\\\\=2^{2\sqrt{3}} *2^{-2\sqrt{3}}-2^{2\sqrt{3}-2}*2^{-2\sqrt{3}}=2^{2\sqrt{3}-2\sqrt{3}}-2^{2\sqrt{3}-2-2\sqrt{3}}=2^{0}-2^{-2}=\\\\=1-\frac{1}{4} =\frac{3}{4}=\boxed{0,75}$