Question

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Answer 1

$\left \{ {{6x+6\geq 0} \atop {18-12x\geq 0}} \right. \\\left \{ {{6x\geq -6} \atop {-12x\geq -18}} \right. \\\left \{ {{x\geq -1\\\\} \atop {x\leq3/2}} \right.$

x∈ [-1 ; 1.5 ]