Question

Помогите решить вопрос

Answer 1

В1:

$3 \sqrt{3} \div \sqrt{48} = 3 \sqrt{3} + \sqrt{16 \times 3} = 3 \sqrt{3} + 4 \sqrt{3} = 7 \sqrt{3}$

В2:

$\frac{ \sqrt{24} }{ \sqrt{8} \times \sqrt{12} } = \frac{ \sqrt{24} }{ \sqrt{96} } = \frac{ \sqrt{4 \times 6} }{ \sqrt{16 \times 6} } = \frac{2 \sqrt{6} }{ 4 \sqrt{6} } = \frac{2}{4} = \frac{1}{2} = 0.5$

В3

$ab {}^{2} \sqrt{b} = \sqrt{a {}^{2} b {}^{4} b} = \sqrt{ {a}^{2} {b}^{5} }$