Question

Пожалуйста помогите с сором дам 45 баллов

Answer 1

№1

$1)3\cdot(k-2p)-5\cdot(2k-p)+(k-3p) = 3k-6p-10k+5p+k-3p = 4k-10k+5p-9p = -6k-4p = -2\cdot(3k+2p)$

$2)7\cdot(a-2b)+11\cdot(b-a)-(2a+3b) = 7a-14b+11b-11a-2a-3b = 7a-13a+11b-17b = -6a-6b = -6\cdot(a+b)$

№2

$(2,5-2\frac{1}{3})\cdot(-5\frac{1}{7})+1\frac{1}{3}:(-5,6)=\frac{13}{21}$

$1) 2,5-2\frac{1}{3} = \frac{25\cdot3}{10\cdot3} - \frac{7\cdot10}{3\cdot10} = \frac{75-70}{30} = \frac{5}{30} = \frac{1}{6}$

$2)\frac{1}{6} \cdot (-5\frac{1}{7}) = \frac{1}{6} \cdot (-\frac{36}{7})=\frac{36}{6\cdot7} = \frac{6}{7}$

$3)1\frac{1}{3} : (-5,6)=\frac{4}{3} : (- \frac{56}{10}) = \frac{4}{3} \cdot (-\frac{10}{56}) = -\frac{4\cdot10}{3\cdot56} = -\frac{5}{21}$

$4)\frac{6}{7} + (-\frac{5}{21}) = \frac{6\cdot3}{7\cdot3} - \frac{5}{21}=\frac{18-5}{21} = \frac{13}{21}$

№3

$15,87\cdot(-1,09)+(-5,87)\cdot(-1,09) = (15,87-5,87)\cdot(-1,09) = 10\cdot(-1,09) = -10,9$

Удачи!