Question

cos ( α - 4π ) sin ( α - 8π ) tg (α - 13π ) Упростите выражение

Answer 1

$cos(\alpha -4\pi )sin(\alpha -8\pi )tg(\alpha -13\pi )=\\=cos\alpha *sin\alpha *tg\alpha =\\=cos\alpha *sin\alpha*\frac{sin\alpha }{cos\alpha } =\\=sin\alpha *sin\alpha =\\=sin\alpha ^2$