Question

ПОМАГИТЕ ПОЖАЛУЙСТА!!!!

Answer 1

Ответ:

39.2

$1)y' = 10 {x}^{4} - 1 \\ 2)y' = 7 {x}^{6} - 4 \times \frac{1}{2} {x}^{ - \frac{1}{2} } = 7 {x}^{6} - \frac{2}{ \sqrt{x} }$

$3)y' = \cos(x) - 2 \sin(x)$

$4)y' = 1 + 5 {x}^{ - 2} = 1 + \frac{5}{ {x}^{2} }$

$5)y' = \frac{1}{ { \sin(x) }^{2} }$

$6)y' = - 2 {x}^{ - 6} = - \frac{2}{ {x}^{6} }$

39.3

$1)y' = {x}^{2} - 4x + 5 + (2x - 4)(x + 2) = {x}^{2} - 4x + 5 + 2 {x}^{2} + 4x - 4x - 8 = 3 {x}^{2} - 4x - 3$

$2)y' = 3( 2{x}^{2} - 1) + 4x(3x + 5) = 6 {x}^{2} - 3 + 12 {x}^{2} + 20x = 18 {x}^{2} + 20x - 3$

$3)y' = 2x \sin(x) + {x}^{2} \cos(x)$

$4)y' = ctg(x) - \frac{x}{ { \sin(x) }^{2} }$

$5)y' = 2 \sqrt{x} + \frac{1}{2 \sqrt{x} } (2x + 1) = 2 \sqrt{x} + \sqrt{x} + \frac{1}{2 \sqrt{x} } = 3 \sqrt{x} + \frac{1}{2 \sqrt{x} }$

$6)y' = \frac{1}{2 \sqrt{x} } \cos(x) - \sqrt{x} \sin(x)$