Question

(tg+5)/2=1/(cos^2 x)

Answer 1

(tgx + 5)/2= 1+tg^2x     tgx +5= 2+2 tg^2x     2tg^2x-tgx-3=0   1. tgx= -1    x= - pi/4+pi*k   
 2.  tgx= 3/2     x= arctg (3/2) +pi*k