Question

ПОМОГИТЕ ПОЖАЛУЙСТА РЕШИТЬ ПРОШУ ДАМ 20 БАЛОВ​

Answer 1

Ответ:

$1) {( \frac{3}{7}) }^{3x - 7} = {( \frac{3}{7} )}^{ - (7x - 3)} \\ 3x - 7 = - 7x + 3 \\ 10x = 10 \\ x = 1$

$2) {5}^{ {x}^{2} - 8x + 12} = {5}^{0} \\ {x}^{2} - 8x + 12 = 0 \\ d = 64 - 48 = 16 \\ x1 = 6 \\ x2 = 2$

$3) {2}^{ {x}^{2} } \div {4}^{x} = 8 \\ {2}^{ {x}^{2} } \div {2}^{2x} = {2}^{3} \\ {2}^{ {x}^{2} - 2x} = {2}^{3} \\ \\ {x}^{2} - 2x = 3 \\ {x}^{2} - 2x - 3 = 0 \\ d = 4 + 12 = 16 \\ x1 = 3 \\ x2 = - 1$

$4) {3}^{x} > {3}^{3} \\ x > 3$

$5) {( \frac{1}{2} )}^{ {x}^{2} - 8x + 18} > {( \frac{1}{2} )}^{3} \\ {x}^{2} - 8x + 18 < 3 \\ {x}^{2} - 8x + 15 < 0 \\ d = 64- 60 = 4 \\ x1 = 5 \\ x2 = 3 \\ (x - 3)(x - 5) < 0$

ответ: х принадлежит (3;5).