Question

-2 (а – в) – 3( а + в) =
-3(2х-у) – 2(х-у) =
5(х-2у) + 3(2х-3у)=

Answer 1

-2(а – b) – 3(а + b) = -2a+2b-3a-3b = -5a-b.

-3(2х - у) – 2(х - у) = -6x+3y-2x+2y = -8x+5y.

5(х - 2у) + 3(2х - 3у) = 5x-10y+6x-9y = 11x-19y.

Answer 2

............................