Question

.Помогииииииитееееееее​

Answer 1

Ответ:

$1) \frac{4x^2-1}{3} = x(10x-9);\\4x^2-1 = 30x^2 - 27x;\\26x^2-27x+1 = 0;\\(26x-1)(x-1) = 0;\\x = 1/26; 1;\\2) \frac{3x^2}{4} - \frac{2x}{5} = \frac{4x^2}{5} + \frac{3}{4}\\15x^2 - 8x = 16x^2+15;\\x^2+8x+15 = 0;\\\\(x+3)(x+5) = 0;\\x = -3; -5;$