Question

sin$\frac{x}{2}$ = -$\frac{\sqrt{3}}{2}$

Answer 1

Ответ:

$sin\dfrac{x}{2}=-\dfrac{\sqrt3}{2}\\\\\\\dfrac{x}{2}=(-1)^{n+1}\cdot \dfrac{\pi}{3}+\pi n\\\\\\x=(-1)^{n+1}\cdot \dfrac{2\pi}{3}+2\pi n\ ,\ n\in Z$