Question

1) sin 60° - 2cos 30° + tg 60°,
2) cos 30º. sin 60° + ctg 600-tg 60°
3) 2 sin 30° - 2cos 30°. tg 30° - cos 0° sin 90°​

Answer 1

Ответ:

1) sin60°-2cos 30°+tg60°= √3/2 - 2 × √3/2 - √3= √3/2 - √3 - √3 = - 3√3/2≈-2,60

3)2sin 30° - 2cos30°.tg30°-cos0° sin90°= 2 × 1/2 - 2 × √3/2 × 1/√3 - 1 × 1 = 1 - 1 - 1=-1

2-ой пример там точно ctg 600?

Answer 2

1)  √3/2 - 2 × √3/2 - √3= √3/2 - √3 - √3 = - 3√3/2≈-2,60

2) 3/4 + ctg(600) -√3

3) 2 × 1/2 - 2 × √3/2 × 1/√3 - 1 × 1 = 1 - 1 - 1=-1