Question

6х+3y-2=0, если y=3 целых 1,3 ​

Answer 1

Ответ:

$y = 3 \frac{1}{3}$

$6x + 3 \times 3 \frac{1}{3} - 2 = 0 \\ 6x + 3 \times \frac{10}{3} - 2 = 0 \\ 6x + 10 - 2 = 0 \\ 6x + 8 = 0 \\ 6x = - 8 \\ x = - \frac{8}{6} \\ x = - \frac{4}{3}$