Question

помогите пожалуйста СРОЧНО!!!​

Answer 1

Ответ:

$1)2 {x}^{2} - 5x - 3 = 0 \\ d = 25 + 24 = 49 = {7}^{2} \\ x1 = \frac{5 + 7}{4} = \frac{12}{4} = 3 \\ x2 = \frac{5 - 7}{4} = - \frac{2}{4} = - \frac{1}{2}$

$2)3 {x}^{2} - 8x + 5 = 0 \\ d = 64 - 60 = 4 = {2}^{2} \\ x1 = \frac{8 + 2}{6} = \frac{10}{6} = 1 \frac{4}{6} = 1 \frac{2}{3} \\ x2 = \frac{8 - 2}{6} = \frac{6}{6} = 1$

Answer 2

Ответ:

1)2x²-5x-3=0 2)3x²-8x+5=0

2x²+x-6x-3=0 3x²-3x-5x+5=0

x×(2x+1)-3(2x+1)=0 3x(x-1)-5(x-1)=0

(2x+1)×(x-3)=0 (x-1)×(3x-5)=0

2x+1=0 x-1=0

x-3=0 3x-5=0

x-2/1 x=1

x=3 x=3/5

x1=-2/1,x2=3 x1=1,x2=3/5