Какой объём (дм3) воздуха необходим для полного обжига сульфида цинка массой 9,7 г?
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Ответ:
2Zns + 3O2 - 2ZnO + 2SO2
n(ZnS)= 9.7/97= 0.1 => n(O2)= 0.15
V(O2)= 0.15*22.4=3.36 => V(воздух) = 3.36*100/20= 16.8 л
Объяснение:
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