Question

умножение многочлена! помогите пж
(x^2 + 2)(x - 3)
(3x^2 - 5x)(2 - x)
(c - 4)(c + 4)
(5x^2 - 6y^2)(6x^2 - 5y^2)
(a^2 + 2b) (2a + b^2)
(x^2 + 2x + 1)(x + 3)

Answer 1

Ответ:

$( {x}^{2} + 2)(x - 3) = {x}^{3} - 3 {x}^{2} + 2 - 6$

$(3 {x}^{2} - 5x)(2 - x) = 6 {x}^{2} - 3 {x}^{3} - 10x + 5 {x}^{2} = 11 {x}^{2} - 3 {x}^{3} - 10x$

$(c - 4)(c + 4) = {c}^{2} + 4c - 4c - 16 = {c}^{2} - 16$

$(5 {x}^{2} - 6 {y}^{2} )(6 {x}^{2} - 5 {y}^{2} ) = 30 {x}^{4} - 25 {x}^{2} {y}^{2} - 36 {x}^{2} {y}^{2} + 30 {y}^{4} = 30 {x}^{4} + 30 {y}^{4} - 61 {x}^{2} {y}^{2}$

$( {a}^{2} + 2b)(2a + {b}^{2} ) = 2 {a}^{3} + {a}^{2} {b}^{2} + 4ab + 2 {b}^{3}$

$( {x}^{2} + 2x + 1)(x + 3) = {x}^{3} + 3 {x}^{2} + 2 {x}^{2} + 6x + x + 3 = {x}^{3} + 5 {x}^{2} + 7x + 3$