Question

(7-3/2):(1 4/3-6/1)×(1 5/1+2 3/2+6/1)=​

Answer 1

Ответ:

$16\dfrac{2}{15}$

Пошаговое объяснение:

Вычислим значение выражения:  

$\displaystyle \tt \left (7-\frac{2}{3} \right ) : \left (1\frac{3}{4}-\frac{1}{6} \right ) \cdot \left (1\frac{1}{5}+2\frac{2}{3} +\frac{1}{6} \right )=16\frac{2}{15}.\\\\1) \; 7-\frac{2}{3} = 6 \frac{3}{3}-\frac{2}{3}=6\frac{1}{3};\\\\2) \; 1\frac{3}{4}-\frac{1}{6}=1\frac{9}{12}-\frac{2}{12}=1\frac{7}{12};\\\\3) \; 1\frac{1}{5}+2\frac{2}{3}=1\frac{3}{15}+2\frac{10}{15}=3\frac{13}{15};\\\\4) \; 3\frac{13}{15}+\frac{1}{6}=3\frac{26}{30}+\frac{5}{30}=3\frac{31}{30}=4\frac{1}{30};$

$\displaystyle \tt 5) \; 6\frac{1}{3}:1\frac{7}{12}=\frac{19}{3}:\frac{19}{12}=\frac{19}{3} \cdot \frac{12}{19}=\frac{12 \cdot 19}{19 \cdot 3}=4;\\\\6) \; 4 \cdot 4\frac{1}{30}=\frac{4}{1} \cdot \frac{121}{30}=\frac{4 \cdot 121}{1 \cdot 30}=\frac{2 \cdot 121}{15}=\frac{242}{15}=16\frac{2}{15}.$