Question

Найти производную функции

Answer 1

Ответ:

${x}^{2} + {y}^{4} - 3 {x}^{2} y = 0 \\ 2x + 4 {y}^{3} y' - 6xy - 3 {x}^{2} y' = 0 \\ y'(4 {y}^{3} - 3 {x}^{2} ) = 6xy - 2x \\ y' = \frac{6xy - 2x}{4 {y}^{3} - 3 {x}^{2} }$